local helpers = require('test.functional.helpers')(after_each) local clear = helpers.clear local eq = helpers.eq local exec_lua = helpers.exec_lua local pcall_err = helpers.pcall_err local matches = helpers.matches local pending_c_parser = helpers.pending_c_parser before_each(clear) describe('treesitter API', function() -- error tests not requiring a parser library it('handles missing language', function() eq("Error executing lua: .../language.lua:0: no parser for 'borklang' language, see :help treesitter-parsers", pcall_err(exec_lua, "parser = vim.treesitter.get_parser(0, 'borklang')")) -- actual message depends on platform matches("Error executing lua: Failed to load parser: uv_dlopen: .+", pcall_err(exec_lua, "parser = vim.treesitter.require_language('borklang', 'borkbork.so')")) -- Should not throw an error when silent eq(false, exec_lua("return vim.treesitter.require_language('borklang', nil, true)")) eq(false, exec_lua("return vim.treesitter.require_language('borklang', 'borkbork.so', true)")) eq("Error executing lua: .../language.lua:0: no parser for 'borklang' language, see :help treesitter-parsers", pcall_err(exec_lua, "parser = vim.treesitter.inspect_language('borklang')")) end) it('inspects language', function() if pending_c_parser(pending) then return end local keys, fields, symbols = unpack(exec_lua([[ local lang = vim.treesitter.inspect_language('c') local keys, symbols = {}, {} for k,_ in pairs(lang) do keys[k] = true end -- symbols array can have "holes" and is thus not a valid msgpack array -- but we don't care about the numbers here (checked in the parser test) for _, v in pairs(lang.symbols) do table.insert(symbols, v) end return {keys, lang.fields, symbols} ]])) eq({fields=true, symbols=true, _abi_version=true}, keys) local fset = {} for _,f in pairs(fields) do eq("string", type(f)) fset[f] = true end eq(true, fset["directive"]) eq(true, fset["initializer"]) local has_named, has_anonymous for _,s in pairs(symbols) do eq("string", type(s[1])) eq("boolean", type(s[2])) if s[1] == "for_statement" and s[2] == true then has_named = true elseif s[1] == "|=" and s[2] == false then has_anonymous = true end end eq({true,true}, {has_named,has_anonymous}) end) end)