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-- Tests for undo tree and :earlier and :later.
local helpers = require('test.functional.helpers')
local feed, insert, source, eq, eval, clear, execute, expect, wait =
helpers.feed, helpers.insert, helpers.source, helpers.eq, helpers.eval,
helpers.clear, helpers.execute, helpers.expect, helpers.wait
local expect_empty_buffer = function()
-- The space will be removed by helpers.dedent but is needed as dedent will
-- throw an error if it can not find the common indent of the given lines.
expect(' ')
end
describe('the undo tree', function()
setup(clear)
teardown(function()
os.remove('Xtest')
end)
it('is working', function()
-- Assert that no undo history is present.
eq({}, eval('undotree().entries'))
insert([[
123456789]])
-- Clear the undo history after the insertion (see :h clear-undo)
execute('let old_undolevels = &undolevels')
execute('set undolevels=-1')
feed('a <BS><Esc>')
execute('let &undolevels = old_undolevels')
execute('unlet old_undolevels')
eq({}, eval('undotree().entries'))
-- Delete three characters and undo.
feed('Gxxx')
eq('456789', eval('getline(".")'))
feed('g-')
eq('3456789', eval('getline(".")'))
feed('g-')
eq('23456789', eval('getline(".")'))
feed('g-')
eq('123456789', eval('getline(".")'))
feed('g-')
eq('123456789', eval('getline(".")'))
-- Delete three other characters and go back in time step by step.
feed('$xxx')
eq('123456', eval('getline(".")'))
execute('sleep 1')
wait()
feed('g-')
eq('1234567', eval('getline(".")'))
feed('g-')
eq('12345678', eval('getline(".")'))
feed('g-')
eq('456789', eval('getline(".")'))
feed('g-')
eq('3456789', eval('getline(".")'))
feed('g-')
eq('23456789', eval('getline(".")'))
feed('g-')
eq('123456789', eval('getline(".")'))
feed('g-')
eq('123456789', eval('getline(".")'))
feed('g-')
eq('123456789', eval('getline(".")'))
feed('10g+')
eq('123456', eval('getline(".")'))
-- Delay for three seconds and go some seconds forward and backward.
execute('sleep 2')
wait()
feed('Aa<esc>')
feed('Ab<esc>')
feed('Ac<esc>')
eq('123456abc', eval('getline(".")'))
execute('ear 1s')
eq('123456', eval('getline(".")'))
execute('ear 3s')
eq('123456789', eval('getline(".")'))
execute('later 1s')
eq('123456', eval('getline(".")'))
execute('later 1h')
eq('123456abc', eval('getline(".")'))
-- Test that setting 'ul' breaks change blocks, we need to use source() in
-- order to test this, as interactive changes are not grouped.
execute('new')
-- First verify that scripts produce single big undo blocks.
source([[
normal Aaaaa
normal obbbb
normal occcc
]])
expect([[
aaaa
bbbb
cccc]])
feed('u')
expect_empty_buffer()
-- Verify that undo blocks can be broken inside scripts by setting 'ul'.
source([[
normal Aaaaa
set ul=100
normal obbbb
set ul=100
normal occcc
]])
expect([[
aaaa
bbbb
cccc]])
feed('u')
expect([[
aaaa
bbbb]])
feed('u')
expect('aaaa')
feed('u')
expect_empty_buffer()
-- Test undojoin.
feed('Goaaaa<esc>')
feed('obbbb<esc>u')
eq('aaaa', eval('getline(".")'))
feed('obbbb<esc>')
execute('undojoin')
feed('occcc<esc>u')
-- TODO At this point the original test will write "aaaa" to test.out.
-- Why is the line "bbbb" here?
eq('bbbb', eval('getline(".")'))
execute('e! Xtest')
feed('ione one one<esc>')
execute('w!')
feed('otwo<esc>')
feed('otwo<esc>')
execute('w')
feed('othree<esc>')
execute('earlier 1f')
expect([[
one one one
two
two]])
execute('earlier 1f')
expect('one one one')
execute('earlier 1f')
expect_empty_buffer()
execute('later 1f')
expect('one one one')
execute('later 1f')
expect([[
one one one
two
two]])
execute('later 1f')
expect([[
one one one
two
two
three]])
execute('enew!')
feed('oa<esc>')
feed('ob<esc>')
feed([[o1<esc>a2<C-R>=setline('.','1234')<cr><esc>]])
expect([[
a
b
12034]])
feed('uu')
expect([[
a
b
1]])
feed('oc<esc>')
feed([[o1<esc>a2<C-R>=setline('.','1234')<cr><esc>]])
expect([[
a
b
1
c
12034]])
feed('u')
expect([[
a
b
1
c
12]])
feed('od<esc>')
feed('o1<esc>a2<C-R>=string(123)<cr><esc>')
expect([[
a
b
1
c
12
d
12123]])
-- TODO there is a difference between the original test and this test at
-- this point. The original tests expects the last line to go away after
-- the undo. I do not know why this should be the case as the "o" and "a"
-- above are seperate changes. I was able to confirm this manually with
-- vim and nvim. Both end up in this state (treat "o" and "a" as two
-- edits).
feed('u')
expect([[
a
b
1
c
12
d
1]])
end)
end)
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